-3+3i in polar form between 0 and 2pi
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-3+3i in polar form between 0 and 2pi

[From: ] [author: ] [Date: 11-05-12] [Hit: ]
......
z = -3 + 3i

= 3(-1 + i)

r = 3√(1+1) = 3√2

θ = tan^-1(1/(-1)) = 3Π/4 (since x is negative and y is positive, θ is in II quadrant)

z = 3√2 [cos(3Π/4) + isin(3Π/4)]
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