z = -3 + 3i
= 3(-1 + i)
r = 3√(1+1) = 3√2
θ = tan^-1(1/(-1)) = 3Π/4 (since x is negative and y is positive, θ is in II quadrant)
z = 3√2 [cos(3Π/4) + isin(3Π/4)]
= 3(-1 + i)
r = 3√(1+1) = 3√2
θ = tan^-1(1/(-1)) = 3Π/4 (since x is negative and y is positive, θ is in II quadrant)
z = 3√2 [cos(3Π/4) + isin(3Π/4)]