1. The perimeter of a standard-sized rectangular rug is 32ft. The length is 2ft longer than the width. Find the dimensions.
What is the width?
What is the length?
2. A flower bed is in the shape of a triangle with one side twice the length of the shortest side, and the third side is 13 feet more than the length of the shortest side. Find the dimensions if the perimeter is 145 feet.
3. A box to hold pencils measures 7.2 inches by 5 inches by 3 inches high. Find the volume of the box.
4. Solve for g.
q= 2g+2v
5. Solve for x.
Dx+Gy= J
What is the width?
What is the length?
2. A flower bed is in the shape of a triangle with one side twice the length of the shortest side, and the third side is 13 feet more than the length of the shortest side. Find the dimensions if the perimeter is 145 feet.
3. A box to hold pencils measures 7.2 inches by 5 inches by 3 inches high. Find the volume of the box.
4. Solve for g.
q= 2g+2v
5. Solve for x.
Dx+Gy= J
-
1)
p=2l+2w
32=2(w+2)+2w
32=2w+4+2w
32=4w+4
32-4=4w
28=4w
7=w
l=w+2
l=7+2
l=9
2)
p=s+s+s
145=s+(2s)+(s+13)
145=4s+13
145-13=4s
132=4s
132/4=s
33=s
33 is side 1, 33(2)=66 is side 2, 33+13=46 is side 3
3)
V=lwh
v=7.2(5)(3)
v=112.5
so 112.5inches^3 is volumes
4)
q=2g+2v
q-2v=2g
1/2q-v=g
5)
dx+gy=j
x+gy=j/d
x=j/d-gy
p=2l+2w
32=2(w+2)+2w
32=2w+4+2w
32=4w+4
32-4=4w
28=4w
7=w
l=w+2
l=7+2
l=9
2)
p=s+s+s
145=s+(2s)+(s+13)
145=4s+13
145-13=4s
132=4s
132/4=s
33=s
33 is side 1, 33(2)=66 is side 2, 33+13=46 is side 3
3)
V=lwh
v=7.2(5)(3)
v=112.5
so 112.5inches^3 is volumes
4)
q=2g+2v
q-2v=2g
1/2q-v=g
5)
dx+gy=j
x+gy=j/d
x=j/d-gy