The round figure that contains the greatest amount of space is a perfect circle. 1. Just divide 180 by 4=45 and you have the dimensions of each side.9. Like the sides of a square , Just add 45 +45=90 and 45 x 45=2025 will give you nthe greates product the same way a square with 45 for each side will give one the greates amount of space.......
this turns out to be the same answer as 8 funny isnt it
you do the derivative
d(product)/dx = 90 - 2x
set derivative to 0
0 = 90 -2x
90 = 2x
x = 45
10 ) is a bit difference
we have 2 same sides and one other side the 4th side is made by the wall
we assume the wall will be longer than the fence because the total length of fence is only 180 feet and the wall is 200 so even if it were laid out straight wouldnt cover the whole wall
2x + y = 180
solve for y
y = 180 - 2x
area = xy = x(180 -2x) = 180x - 2x^2
d(area)/dx = 180 - 4x
set derivative to 0
0 = 180 - 4x
4x = 180
x = 45
y = 180 - 2x
y = 180 - 90
y = 90
so the dimensions of the pen are 45 by 90
I hope that helps I broke down each step as good as I could
My goodness marris! First, let me state two facts: 1. the rectangle which contains the largest amount of space is a square. The round figure that contains the greatest amount of space is a perfect circle. 1. Just divide 180 by 4=45 and you have the dimensions of each side.9. Like the sides of a square , Just add 45 +45=90 and 45 x 45=2025 will give you nthe greates product the same way a square with 45 for each side will give one the greates amount of space. 10. Just assume that 180 is the length of 3 sides of a square; therefore 180/3 =60 = the sides of a square with the wall 60 ft long being the 4th. side. Area = 3,600
