8. You have 180 feet of fence to make a regular pen. What are the dimensions of the rectangle with the maximum area?
The answer's supposed to be 45ft by 45ft but idk y
9. Of all the pairs of real numbers that have sum 90, which pair has the greatest product?
do i write an equation?
10. You have 180 feet of fence to make a rectangle pen. One side of the pen will be against a 200 ft wall, so it requires no fence. What are the dimensions of the rectangle with the maximum.
The answer's supposed to be 45ft by 45ft but idk y
9. Of all the pairs of real numbers that have sum 90, which pair has the greatest product?
do i write an equation?
10. You have 180 feet of fence to make a rectangle pen. One side of the pen will be against a 200 ft wall, so it requires no fence. What are the dimensions of the rectangle with the maximum.
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8) the 180 feet of fence to make a regular pen in shape of rectangle
ok you want to maximize the area function
let x = one side dimension
let y = other side dimension
now we know that we have only 180 feet so
2x + 2y = 180
that is 2 y sides and 2 x sides make a rectangle
notice we didnt make the assumption that the sides are the same
now for area
A = xy
this is complicated because it has y in it
if we use the other formula for length solve for y we can substitute that in for the y in the area and have an equation in x only
2x + 2y = 180
2y = 180 - 2x
y = 90 - x
putting in the area equation
Area = xy = x(90 -x)
area = 90x - x^2
we want to maximize the area do the derivative
d(area)/dx = 90 -2x
this is max or min when it equals 0
0 = 90 -2x
2x = 90
x = 45
d^2(area)/dx^2 = -2
since second derivative is negative slope is decreasing and so its a hump and therefor a maximum
so when x = 45 Area is maximum that makes
y = 90 -x = 90 -45 = 45
9)
same thing with 9 make the equations
a pair of numbers is x and y
so x + y = 90 means there sum is 90
x * y = product
use the first one to solve for y again .. you could solve for x if you wanted but I picked y
y = 90 - x
x(90 -x) =product
product = 90x - x^2
ok you want to maximize the area function
let x = one side dimension
let y = other side dimension
now we know that we have only 180 feet so
2x + 2y = 180
that is 2 y sides and 2 x sides make a rectangle
notice we didnt make the assumption that the sides are the same
now for area
A = xy
this is complicated because it has y in it
if we use the other formula for length solve for y we can substitute that in for the y in the area and have an equation in x only
2x + 2y = 180
2y = 180 - 2x
y = 90 - x
putting in the area equation
Area = xy = x(90 -x)
area = 90x - x^2
we want to maximize the area do the derivative
d(area)/dx = 90 -2x
this is max or min when it equals 0
0 = 90 -2x
2x = 90
x = 45
d^2(area)/dx^2 = -2
since second derivative is negative slope is decreasing and so its a hump and therefor a maximum
so when x = 45 Area is maximum that makes
y = 90 -x = 90 -45 = 45
9)
same thing with 9 make the equations
a pair of numbers is x and y
so x + y = 90 means there sum is 90
x * y = product
use the first one to solve for y again .. you could solve for x if you wanted but I picked y
y = 90 - x
x(90 -x) =product
product = 90x - x^2
12
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