Can you please tell me HOW I prove that the following geometric series is either CONDITIONALLY or ABSOLUTELY convergent?
sum of (-2/3)^n from n=1 to infinity
sum of (-2/3)^n from n=1 to infinity
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Using the ratio test,
r = lim(n→∞) |(-2/3)^(n+1) / (-2/3)^n| = 2/3 < 1.
Hence, the series converges absolutely.
I hope this helps!
r = lim(n→∞) |(-2/3)^(n+1) / (-2/3)^n| = 2/3 < 1.
Hence, the series converges absolutely.
I hope this helps!