Fairly easy question about convergence of this series
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Fairly easy question about convergence of this series

[From: ] [author: ] [Date: 11-05-11] [Hit: ]
......
Can you please tell me HOW I prove that the following geometric series is either CONDITIONALLY or ABSOLUTELY convergent?
sum of (-2/3)^n from n=1 to infinity

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Using the ratio test,
r = lim(n→∞) |(-2/3)^(n+1) / (-2/3)^n| = 2/3 < 1.

Hence, the series converges absolutely.

I hope this helps!
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