"If tickets are sold for $45 each, then 600 tickets are expected to be sold.
For each $1 reduction in price, an additional 22 tickets will be sold."
the function i figured was f(x)= (45-x)(600+22x)
I am then asked to find the ticket price that results in 45,000, what do i go about doing next to find this? round to the nearest cent.
For each $1 reduction in price, an additional 22 tickets will be sold."
the function i figured was f(x)= (45-x)(600+22x)
I am then asked to find the ticket price that results in 45,000, what do i go about doing next to find this? round to the nearest cent.
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45000 = (45 - x)(600 + 22x)
foil out the right to get
45000 = 27000 + 390x - 22x²
subtract 45000 from both sides and use the quadratic eqn to get x.
0 = -18000 + 390x - 22x²
x = [-b ± √(b² - 4ac)]/2a, where a = -22, b = 390, and c = -18000
when you solve you'll get two complex solutions, so there is no ticket price that will result in $45,000 in sales. also, if you graph your original function, you'll see that the max amount of sales is $28,728
foil out the right to get
45000 = 27000 + 390x - 22x²
subtract 45000 from both sides and use the quadratic eqn to get x.
0 = -18000 + 390x - 22x²
x = [-b ± √(b² - 4ac)]/2a, where a = -22, b = 390, and c = -18000
when you solve you'll get two complex solutions, so there is no ticket price that will result in $45,000 in sales. also, if you graph your original function, you'll see that the max amount of sales is $28,728