How do I verify this identity?
(sec x + csc x) / (sin x + cos x) = 2 / (sin 2x)
I have no idea what to do, please help!
Thanks
(sec x + csc x) / (sin x + cos x) = 2 / (sin 2x)
I have no idea what to do, please help!
Thanks
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RHS simplifies to 2/(2*sin(x)*cos(x)) = csc(x)*sec(x)
LHS also simplifies to:
(1/cos x + 1/sin x)/(sin x + cos x) = (1/sin(x)*cos(x)) = csc(x)*sec(x)
LHS also simplifies to:
(1/cos x + 1/sin x)/(sin x + cos x) = (1/sin(x)*cos(x)) = csc(x)*sec(x)
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( sec x + csc x)/( sin x + cos x)
= [ (1/ cos x) + (1/ sin x) ]/ (sin x + cos x)
= [ sin x + cos x] /sin x cos x (sin x + cos x)
= 1/ sin x cos x
= 1 / (1/2) sin(2x)
= 2 / sin(2x)
= [ (1/ cos x) + (1/ sin x) ]/ (sin x + cos x)
= [ sin x + cos x] /sin x cos x (sin x + cos x)
= 1/ sin x cos x
= 1 / (1/2) sin(2x)
= 2 / sin(2x)
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Rewrite them in terms of sin.