It says consider the following problem...
a. 33 b. 25 c. 52
Is this triangle I right triangle.
I added AB, AC, and BC and got
58, 85, 77
How do I know if it is a right triangle or not?
a. 33 b. 25 c. 52
Is this triangle I right triangle.
I added AB, AC, and BC and got
58, 85, 77
How do I know if it is a right triangle or not?
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a^2 + b^2 = c^2
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The three given sides are, 33, 25, 52
If it is a right angled triangle hypotenuse would be 52 (the biggest side)
If it satisfy the equation ac^2= ab^2+bc^2 it is right angled triangle.
(52)^2 = (33)^2 + (25)^2
2704= 1089+ 625
2704= 1714 (!!!!!!!!!!!!!!!)
Can this ever be true!??? So the given set do not form a right angle.
Hope you understood the logic! Thank you
If it is a right angled triangle hypotenuse would be 52 (the biggest side)
If it satisfy the equation ac^2= ab^2+bc^2 it is right angled triangle.
(52)^2 = (33)^2 + (25)^2
2704= 1089+ 625
2704= 1714 (!!!!!!!!!!!!!!!)
Can this ever be true!??? So the given set do not form a right angle.
Hope you understood the logic! Thank you
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to know --
first -
multiply 52*52 = 2704 , 33*33 = 1089 , 25*25 = 625
for right angle triangle ---> 52*52 = 33*33 + 25*25
check that -
add --
33*33 + 25*25 = 1089 + 625 = 1714
clearly this is not equal to 52*52 = 2704 , so its not a right angle triangle
first -
multiply 52*52 = 2704 , 33*33 = 1089 , 25*25 = 625
for right angle triangle ---> 52*52 = 33*33 + 25*25
check that -
add --
33*33 + 25*25 = 1089 + 625 = 1714
clearly this is not equal to 52*52 = 2704 , so its not a right angle triangle
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just go by pythagoras theorem and check whether the sum of the squares of the 2 smallest sides is equal to the square of the third side
so in this case 33^2 + 25^2 = 1714 is not equal to 52^2 so it is not a right triangle
so in this case 33^2 + 25^2 = 1714 is not equal to 52^2 so it is not a right triangle
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throw it against the wall, if it sticks it's a right triangle.