AB = a + tb and CD = a + (3t – 5)b where t is a number.
Find the value of t when AB = CD .
I need a step by step answer please.
Thanks!
Find the value of t when AB = CD .
I need a step by step answer please.
Thanks!
-
if AB = CD
then
a + tb = a + (3t - 5)b
→ tb = (3t - 5)b
→ t = (3t - 5)
→ -2t = -5
→ t = 5/2
then
a + tb = a + (3t - 5)b
→ tb = (3t - 5)b
→ t = (3t - 5)
→ -2t = -5
→ t = 5/2