y=a(x-h)^2+k
(x-h)^2=4p(y-k)
(y-k)^2=4p(x-h)
How are the first two equations equivalent?
(x-h)^2=4p(y-k)
(y-k)^2=4p(x-h)
How are the first two equations equivalent?
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y = a(x-h)² + k
y-k = a(x-h)²
(x-h)² = (1/a)(y-k)
which is equivalent to
(x-h)² = 4p(y-k)
if 4p = 1/a
y-k = a(x-h)²
(x-h)² = (1/a)(y-k)
which is equivalent to
(x-h)² = 4p(y-k)
if 4p = 1/a