im stuck on these last few problems...i've already done a bunch of other problems similar to itt. mathematicians please help!!
1. √x^9
(a) x^4 √x
(b) 2x√x
(c) 3x√2x
2. ^3√54x^11
(a) 2x^2√2x^2
(b) 5^3√2x
(c) 3x^3 ^3√2x^2
3. ^3√128x^6
(a) 4x^2 ^3√2
(b) x^3√2x^2
(c) 2x^2√2x^2
4. ^3√-27x^5
(a) 5 ^3√2x
(b) x√2x^2
(c) -3x^3√x^2
5. ^4√16x^7
(a) x√2x^2
(b) 2x^4√x^3
(c) 2x^2√2x^2
6. ^4√162^6
(a) 3x^4√2x^2
(b) x^3√2x^2
(c) 5 ^3√2x
its 6 problems...i think it looks like allot more cause its just allot of numbers haha 10 points for 6 problems!! smart mathematicians pleaseeee helppp. thank you so much!
1. √x^9
(a) x^4 √x
(b) 2x√x
(c) 3x√2x
2. ^3√54x^11
(a) 2x^2√2x^2
(b) 5^3√2x
(c) 3x^3 ^3√2x^2
3. ^3√128x^6
(a) 4x^2 ^3√2
(b) x^3√2x^2
(c) 2x^2√2x^2
4. ^3√-27x^5
(a) 5 ^3√2x
(b) x√2x^2
(c) -3x^3√x^2
5. ^4√16x^7
(a) x√2x^2
(b) 2x^4√x^3
(c) 2x^2√2x^2
6. ^4√162^6
(a) 3x^4√2x^2
(b) x^3√2x^2
(c) 5 ^3√2x
its 6 problems...i think it looks like allot more cause its just allot of numbers haha 10 points for 6 problems!! smart mathematicians pleaseeee helppp. thank you so much!
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1. √(x^8 * x)
= x^4√(x)
2. ∛(27*2*x^9*x²)
= 3x³∛(2x²)
3. ∛(128x^6)
= x²∛(64*2)
= 4x²∛(2)
4. ∛(-27x^5)
= -3x∛(x²)
5. ∜(16x^7)
= 2x∜(x³)
6. ∜(162x^6)
= 3x∜(2x²)
I hope this helps!
= x^4√(x)
2. ∛(27*2*x^9*x²)
= 3x³∛(2x²)
3. ∛(128x^6)
= x²∛(64*2)
= 4x²∛(2)
4. ∛(-27x^5)
= -3x∛(x²)
5. ∜(16x^7)
= 2x∜(x³)
6. ∜(162x^6)
= 3x∜(2x²)
I hope this helps!
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1. A square root can also be written as x^1/2 so we have (x^9)^1/2
and you multiply them
X^9/2 Which is also written 4 1/2
(a) X^4 √x
2. We may also write 54^1/3 x^11/3
54 = 2 x 27
27 = 3 x 9
9 = 3 x 3
so 54 = 2 x 3 x 3 x 3
(3^√2) x (3^√(3 x 3 x 3)) = 3 3^√2
x also equals =x^11/3 re-written x^3 x^2/3
Also re-written (c) 3x^3 3^√2x^2 (Oh god I hope that doesn't look confusing)
3. 3. ^3√128x^6
Simple
re-write is as 3^√128 and x^6/3
Now 128 can also be broken down into
3^√2x2x2x2x2x2x2
so we can break it up to look like
3^√2x2x2 3^√2x2x2 3^√2
that's 4√2
x is just x^2
So answer is!
(a)4x^2 3^√2
4. ^3√-27x^5
You're not allowd to take a square root of a negative...although
you can re-write it
- 3^√3X3X3 x^5/3
That's (c)-3x 3^√x^2
5. 4^√16x^7
Also re-written as
4^√2x2x2x2 x^7/4
2x 4^√x^3
Answer (b)
6. 4^√162^6
There are no x's.... So I don't see how...
Either way you can still simplify the numeric number
162^6/4
or 162^3/2
Or 162 √162 I believe.
and you multiply them
X^9/2 Which is also written 4 1/2
(a) X^4 √x
2. We may also write 54^1/3 x^11/3
54 = 2 x 27
27 = 3 x 9
9 = 3 x 3
so 54 = 2 x 3 x 3 x 3
(3^√2) x (3^√(3 x 3 x 3)) = 3 3^√2
x also equals =x^11/3 re-written x^3 x^2/3
Also re-written (c) 3x^3 3^√2x^2 (Oh god I hope that doesn't look confusing)
3. 3. ^3√128x^6
Simple
re-write is as 3^√128 and x^6/3
Now 128 can also be broken down into
3^√2x2x2x2x2x2x2
so we can break it up to look like
3^√2x2x2 3^√2x2x2 3^√2
that's 4√2
x is just x^2
So answer is!
(a)4x^2 3^√2
4. ^3√-27x^5
You're not allowd to take a square root of a negative...although
you can re-write it
- 3^√3X3X3 x^5/3
That's (c)-3x 3^√x^2
5. 4^√16x^7
Also re-written as
4^√2x2x2x2 x^7/4
2x 4^√x^3
Answer (b)
6. 4^√162^6
There are no x's.... So I don't see how...
Either way you can still simplify the numeric number
162^6/4
or 162^3/2
Or 162 √162 I believe.