A person on top of a 200 foot tall building throws a baseball upward with a vertical velocity of 55 feet per second from a height of 207 feet. Write a function describing the height of the ball, in feet, above the ground after t seconds. What is the maximum height the ball will reach? How long will it take the ball to reach its maximum height? When will the ball hit the ground below?
Please solve this, explain to me how you solved it, and give the correct answer. I really have no idea how to do this and I have a test tomorrow! :(
Please solve this, explain to me how you solved it, and give the correct answer. I really have no idea how to do this and I have a test tomorrow! :(
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h(t) = 207 + 55t -- 16t^2 after t seconds of throw
at h(max) v = 0 given by t = 55/32 seconds
h(max) = 207 + 55(55/32) -- 16(55/32)^2 feet = this you find out easily
the ball reaches ground when h = 0 = 207 + 55t -- 16t^2 giving t = 7.42 seconds
at h(max) v = 0 given by t = 55/32 seconds
h(max) = 207 + 55(55/32) -- 16(55/32)^2 feet = this you find out easily
the ball reaches ground when h = 0 = 207 + 55t -- 16t^2 giving t = 7.42 seconds
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can you edit and throw in some equations that you have that involve height and/or velocity. I'm a bit rusty on my physics :)