Use a system of equations and elimination to solve this problem:
Anita is 4.5 years older than Basilio. Three times Anita's age added to six times Basilio's age is 36. How old are Anita and Basilio?
Anita is 4.5 years older than Basilio. Three times Anita's age added to six times Basilio's age is 36. How old are Anita and Basilio?
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A = Anita's age
B = Basilio's age
A = B + 4.5
3A + 6B = 36
A-B = 4.5
3A + 6B = 36
-3A+3B= -13.5
3A + 6B = 36
add them...
9B = 22.5
B = 2.5
A=B+4.5
A=2.5+4.5
A=7
B = Basilio's age
A = B + 4.5
3A + 6B = 36
A-B = 4.5
3A + 6B = 36
-3A+3B= -13.5
3A + 6B = 36
add them...
9B = 22.5
B = 2.5
A=B+4.5
A=2.5+4.5
A=7
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let Basillo = B and Anita = A
A = B+4.5
therefore B = A - 4.5
3A + 6B = 36
(now substitute A = B+4.5 into this equation to get Basilios age)
3(B+4.5) + 6B = 36
3B+13.5+6B = 36
9B = 22.5
therefore B = 2.5 Basilio is 2.5years old
then substitute B = 2.5 into 3A+6B = 36 to get Anitas age or substitute B=A-4.5
you should get the same answer (you can use the 2nd method as a check to see if you correct)
A = 7
A = B+4.5
therefore B = A - 4.5
3A + 6B = 36
(now substitute A = B+4.5 into this equation to get Basilios age)
3(B+4.5) + 6B = 36
3B+13.5+6B = 36
9B = 22.5
therefore B = 2.5 Basilio is 2.5years old
then substitute B = 2.5 into 3A+6B = 36 to get Anitas age or substitute B=A-4.5
you should get the same answer (you can use the 2nd method as a check to see if you correct)
A = 7