It's not like the ones I've seen before. The answer I think is E, but why? And how am I supposed to do this problem if the problem doesn't even mention the variable K and it's present in all the answer choices?
http://img709.imageshack.us/img709/1341/…
http://img709.imageshack.us/img709/1341/…
-
Think of Rolle's Theorem.
If f is continuous on [-2, 2] and differentiable on (-2, 2), and f(-2) = f(2) = 0, then there must exist c in (-2,2) such that f '(c) = 0.
Since the last statement does not hold, we must have that f is not differentiable on (-2, 2) [because we know that f is continuous on [-2, 2] and f(-2) = f(2) = 0].
This leave choice E.
I hope this helps!
If f is continuous on [-2, 2] and differentiable on (-2, 2), and f(-2) = f(2) = 0, then there must exist c in (-2,2) such that f '(c) = 0.
Since the last statement does not hold, we must have that f is not differentiable on (-2, 2) [because we know that f is continuous on [-2, 2] and f(-2) = f(2) = 0].
This leave choice E.
I hope this helps!