A spice jar is 3 inches tall and 1.5 inches in diameter. A funnel is 2 inches tall and 2.5 inches in diameter. If Brett fills the funnel with pepper to put into the spice jar, will it overflow? Explain?
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Assuming the volume in the spout of the funnel is negligible:
Vjar = 3π(1.5)²/4 = 1.6875π in³
Vfunnel = (1/3)(2)(2.5)²π/4 ≈ 1.042π
Since the volume of the funnel is less than the volume of the jar the jar will not overflow (unless the volume of the funnel's spout is not negligible, after all)
Vjar = 3π(1.5)²/4 = 1.6875π in³
Vfunnel = (1/3)(2)(2.5)²π/4 ≈ 1.042π
Since the volume of the funnel is less than the volume of the jar the jar will not overflow (unless the volume of the funnel's spout is not negligible, after all)
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to answer this question, find the volume of the jars using the formula for cylinder which is
pi (3.14) times the radius(which is half the diameter) squared (the radius times itself) times the height (jar 1=3, e.t.c)
the answer will be in the unit "squared inches."
If the funnel has a bigger volume then that means it will overflow as it fits more pepper than the spice jar can hold.
pi (3.14) times the radius(which is half the diameter) squared (the radius times itself) times the height (jar 1=3, e.t.c)
the answer will be in the unit "squared inches."
If the funnel has a bigger volume then that means it will overflow as it fits more pepper than the spice jar can hold.
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No it will not :
Volume of Cylinder = π r^2 h = π (.75)^2 (3) = 5.3 cu inches
while for the funnel :
Vol = V = (1/3) π r^2) h = (1/3) π (1.25^2 (2 ) = 3.27 cu inches
One cannot " guess" at such questions... One has to do the Math !!
Volume of Cylinder = π r^2 h = π (.75)^2 (3) = 5.3 cu inches
while for the funnel :
Vol = V = (1/3) π r^2) h = (1/3) π (1.25^2 (2 ) = 3.27 cu inches
One cannot " guess" at such questions... One has to do the Math !!
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overflow because the diameter of the funnel is bigger than the diameter of the jar