Find the derivative...
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Find the derivative...

[From: ] [author: ] [Date: 11-05-01] [Hit: ]
.....Here its proved in few steps.......
How do I find the derivative of this function:

2x/[(x^2+1)^1/2]?

I'm having such I hard time finding this derivative:s I've spent over an hour trying to get the textbook answer of f'(x)=2/(x^2+1)^3/2.

Thanks(:

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ok let's mae it together:

f (x) = [ 2(x^2+1)^1/2 - 2x[ 2x/ 2(x^2+1)^1/2] ] / (x^2 + 1)

... to simplify well multiply by (x^2+1)^1/2 / (x^2+1)^1/2 and then u get :

f '(x) = [ 2(x^2 + 1) - 2x^2] / (x^2 + 1)^3/2 ... u can easily show that

s f '(x) = (2x^2 + 2 - 2x^2) / / (x^2 + 1)^3/2

...f '(x) = 2 / (x^2 + 1)^3/2

Here it's proved in few steps.

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lodhi/hidlo
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