please help with lots of details explaining why you did what you did. greatly appreciate it, thanks
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factoring is basically the question instead of the answer. when it says to factor something, you are looking for the factors of the numbers being multiplied. http://mathway.com/problem.aspx?p=algebr… this site can factor anything and give you an answer, you need to pay if you want it to show you the steps though. x(x+3)(x-2) this is the factored form. you need x to have an exponent of three and 2. so knowing this, you should be able to work backwards and get the original. that's a way to check. im not so good at factoring myself. so hopefully i helped you the best i can
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Take out the common factor of X to get
x(x^2 + x - 6)=0
Then factor the parentheses. 3 and 2 multiply to equal 6, and they subtract to equal 1, so that's what you want to use.
x(x-2)(x+3)=0 --want to watch the positive and negative signs here to get the right result
So x=0, x=2 and x=-3
x(x^2 + x - 6)=0
Then factor the parentheses. 3 and 2 multiply to equal 6, and they subtract to equal 1, so that's what you want to use.
x(x-2)(x+3)=0 --want to watch the positive and negative signs here to get the right result
So x=0, x=2 and x=-3
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First take out a x.
The problem would be x(x^2+x-6).
Then set everything equal to zero. x=0, x^2+x-6=0
Factor (x+3)(x-2)=0
Set each of those equal to 0. x+3=0 x-2=0
Solve for x. x=-3, x=2
So your final answers would be x=0,-3,2
Hope this is what you were looking for :)
The problem would be x(x^2+x-6).
Then set everything equal to zero. x=0, x^2+x-6=0
Factor (x+3)(x-2)=0
Set each of those equal to 0. x+3=0 x-2=0
Solve for x. x=-3, x=2
So your final answers would be x=0,-3,2
Hope this is what you were looking for :)