Math help please and thanks

One card is selected at random from a deck of cards. Determine the probability that the card is a jack or an ace.

1/2
1/26
2/13
3/13
1/13

Im assuming there are no jokers.
4 jacks
4 aces
52 cards

(4+4)/52
=8/52
=2/13

we know,
4 jacks and 4 aces are present in total 52 cards.

so if one card is selected at random from a deck of cards the probability that the card is a jack or an ace = (4 + 4) / 52 = 8 / 52 = 2 / 13

answer: 2 / 13

4 jacks and 4 aces = 8
total number of cards = 52
so it's 8/52, which is 2/13 simplified

2/13 chance of getting a jack or an ace.

or a 15.4% chance of pulling a jack or an ace

there are 4 J and 4 A in a deck of 52 cards
Hence

J OR A = 4/52 + 4/52 (note OR means +, AND means *)

hence answer is 8/52 = 2/13

The answer is 2/13
There are 4 jacks and 4 aces which means 8 total cards you are wanting. so you divide 52/8 and find common factors to get 2/13