Factoring a trig function

I need help factoring: 2cot^2 (x) + cot(x) - 3 ?? Even if you just help me start, that works too. :)

Let x=Cot(x)
And plug in this substitution:
2x^2+x-3, and you should know how to factor this:

(2x+3)(x-1).
We will then back substitute the original "variable" cos(x)=x into what we factored:

(2cos(x)+3)(cos(x)-1), which is your answer.

2cot^2 (x) + cot(x) - 3
=(2cot(x)+3)(cot(x)-1) answer//