Three collinear vectors a, b, c, are such that a = 2/3 b, and a = 1/2 c
Determine m and n such that mc + nb = 0
Ok how do I do this? I am getting 0 for both m and n, which makes sense. But according to my book, the answer is m = 4, and n = -3 (which is also right, I checked).
Help?
Determine m and n such that mc + nb = 0
Ok how do I do this? I am getting 0 for both m and n, which makes sense. But according to my book, the answer is m = 4, and n = -3 (which is also right, I checked).
Help?
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There are infinitely many solutions. But in general, the trivial solution m = n = 0 is of no real interest.
You can use the fact that a = 2/3 b = 1/2 c ==> b = 3/4 c.
Expanding on this:
4b = 3c ==> 4b - 3c = 0.
This is the answer in your text. But note that you can take m = 4k and n = -3k for any real number k and have a solution. So the answer is not unique.
You can use the fact that a = 2/3 b = 1/2 c ==> b = 3/4 c.
Expanding on this:
4b = 3c ==> 4b - 3c = 0.
This is the answer in your text. But note that you can take m = 4k and n = -3k for any real number k and have a solution. So the answer is not unique.