sec^2x
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(secx)^2
Explanation:
y = tanx = sinx/cosx
Using the quotient rule:
dy/dx = {(cosx)(cosx) - (sinx)(-sinx)}/(cosx)^2
dy/dx = 1/(cosx)^2
dy/dx = (secx)^2
Explanation:
y = tanx = sinx/cosx
Using the quotient rule:
dy/dx = {(cosx)(cosx) - (sinx)(-sinx)}/(cosx)^2
dy/dx = 1/(cosx)^2
dy/dx = (secx)^2
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Derivetive of tanx = sec^2 x
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Secant sqaure ex