Find the inverse of the function f.
f(x) = x^2, x≥0
Use a graphing utility to graph both f and f-1 in the same viewing rectangle. Describe the relationship between the graphs
For f(x)= x^2 i got f^-1(x)= square root of x, for x≥0 i don't know how to solve, i also graphed the functions, but i don't know how to explain the relationship. Can you please help?
Thanks for the ones who helped. :)
f(x) = x^2, x≥0
Use a graphing utility to graph both f and f-1 in the same viewing rectangle. Describe the relationship between the graphs
For f(x)= x^2 i got f^-1(x)= square root of x, for x≥0 i don't know how to solve, i also graphed the functions, but i don't know how to explain the relationship. Can you please help?
Thanks for the ones who helped. :)
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A function has an inverse if and only if its graph intersects any horizontal line at most one time.
f (x) = x^2 does not satisfy this rule, therefore it has no inverse function, so we can say that it is not invertible.
f (x) = x^2 does not satisfy this rule, therefore it has no inverse function, so we can say that it is not invertible.
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I think the inverse of f(x) would be f(x)^-1 and it would be equal to 1/x^2.Th graph of x^2, x=> 0 would be a curved line upward to the right and the inverse of this curve would be the mirror image of same. Be best to double check this.
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y=x^2, re write in terms of x, if trying to find inverse replace y with x
if pre image, dont replace
if pre image, dont replace
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how can i graph for u ???