Why are square of a number and square roots so special

[From: ] [author: ] [Date: 11-04-23] [Hit: ]

The right side has units of kg * m^k / s^k.-Hi:1) because they are inverse of each other2) you use the square to find Area of asquare when the side is knownand the other when the area is known and need to find the side3) there are used in solvequadratic equationsto find the two values of x from thecoefficients of it 4) the law of motion use it KE = 1/2 mA^25) for E =mc^2is due to the equation of MotionK.......

Now, let's look at the right side. m is mass, measured in kg. c^2 is the speed of light, measured in m/s. Thus mc^2 is kg * m^2 / s^2, which matches the units of E!

Notice that this dimensional analysis doesn't tell you ANYTHING about constants. You couldn't disprove E = 1/2 mc^2, or E = pi * mc^2, or E = SQRT(2) * mc^2, since 1/2, pi, and SQRT(2) are dimensionless constants. However, you could easily see that if you knew that E = m * c^k, where you didn't know the constant k, that the ONLY way for the units to match up would be to let k=2. The left side still has units of kg * m^2 / s^2. The right side has units of kg * m^k / s^k.

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Hi:

1) because they are inverse of each other
2) you use the square to find Area of a square when the side is known and the other when the area is known and need to find the side

3) there are used in solve quadratic equations to find the two values of x from the coefficients of it

4) the law of motion use it KE = 1/2 mA^2

5) for E =mc^2 is due to the equation of Motion K.E = 1/2 mA^2 since two Atoms masses are involved in fusing them or are made when spitting it in two So - the 1/2 is dropped and since A is acceleration of the two atoms and it being driven to C the speed of light So A = C and we get E = mc^2

and if you take 2KE/ A^2 = m Or E/C^2 = m you get Matter and Antimatter and put the two together you sqrt (E/m) = c or light in the form of very high Energy wavelengths

I hope this helps

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