sec 2A + tan 2A = ( cosA + sin A ) / ( cos A - sin A)
please help me in proving the identities, from both side is preferable. Thanks a lot! :D
please help me in proving the identities, from both side is preferable. Thanks a lot! :D
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L.H.S
1/cos2A + sin2A/cos2A
= 1+sin2A/cos2A
=[cosA+sinA]^2/[cos^2A-sin^2A]
=[cosA+sinA]^2/(cosA+sinA)(cosA-sinA)
=cosA+sinA/cosA-sinA
1/cos2A + sin2A/cos2A
= 1+sin2A/cos2A
=[cosA+sinA]^2/[cos^2A-sin^2A]
=[cosA+sinA]^2/(cosA+sinA)(cosA-sinA)
=cosA+sinA/cosA-sinA