Let f (x , y) = 32x^2 - 5y
Find the equations of the level curves for the heights z given below.
When z = 0,
the level curve is y = ........................
When z = 1,
the level curve is y = ......................
When z = 2,
the level curve is y = ...................
thank you
Find the equations of the level curves for the heights z given below.
When z = 0,
the level curve is y = ........................
When z = 1,
the level curve is y = ......................
When z = 2,
the level curve is y = ...................
thank you
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f(x,y) is the same as z. So just put in each value for z and solve for y:
0 = 32x^2 - 5y
y = 32x^2/5
1 = 32x^2 - 5y
y = (32x^2 - 1)/5
2 = 32x^2 - 5y
y = (32x^2 - 2)/5
0 = 32x^2 - 5y
y = 32x^2/5
1 = 32x^2 - 5y
y = (32x^2 - 1)/5
2 = 32x^2 - 5y
y = (32x^2 - 2)/5
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You have to put something in for x and solve for y and then put something in for y and solve for x. I haven't done this in years though so I don't really remember, sorry