Can you solve these?
1) 7c^(2) = 100
2) 5n^(2) - 17 = -19
these next few involve the quadratic formula
3) 6x^(2) - 2x - 28 = 0
4) -2x^(2) + 5 = 3x^(2) - 10x
5) 3x^(2) - 4 = 11x
1) 7c^(2) = 100
2) 5n^(2) - 17 = -19
these next few involve the quadratic formula
3) 6x^(2) - 2x - 28 = 0
4) -2x^(2) + 5 = 3x^(2) - 10x
5) 3x^(2) - 4 = 11x
-
1) 7c² = 100
Divide both sides by 7.
c² = 100/7
Take the square root of both sides. Don't forget ± since 2 is an even power.
c = ±10/√7
2) 5n² -17 = -19
Add 17 to both sides.
5n² = -2
This will result in imaginary numbers. If you wish to proceed, follow the steps for question 1.
For a quadratic equation:
ax² + bx + c = 0
The roots can be solved for using the quadratic formula:
x = [-b ± √(b² - 4ac)] / (2a)
Just plug in each equation for a, b, c and simplify.
Divide both sides by 7.
c² = 100/7
Take the square root of both sides. Don't forget ± since 2 is an even power.
c = ±10/√7
2) 5n² -17 = -19
Add 17 to both sides.
5n² = -2
This will result in imaginary numbers. If you wish to proceed, follow the steps for question 1.
For a quadratic equation:
ax² + bx + c = 0
The roots can be solved for using the quadratic formula:
x = [-b ± √(b² - 4ac)] / (2a)
Just plug in each equation for a, b, c and simplify.