Trigonometry please help

sin150/ cos300 - tan300/cos330

sin300/sin240 - tan150/240

sin 150/cos 300 - tan 300/cos 330 =sin (180-30)/cos(360-60) -tan(360-60)/cos (360-30)
=sin 30/cos 60 - (-tan 30)/cos 30 =0.5/0.5 + 1.73205/ 0.86603 =1+ 2 =3


sin300/sin240 - tan150/240 =sin(360-60)/sin(180+60) - tan(180-30)/240 = -sin 60/-sin 60 - (-tan 30)/ a =1 + (0.57735/ a )
a is not given n the question

Q1. sin150/ cos300 - tan300/cos330
Sol sin(150)/ cos(300) - tan(300)/cos(330)
= {sin(180 -30)/ cos(360 -60)} - { tan(360-60)/ cos(360-30)}
= (sin(30)/cos(60) } - { -tan(60)/cos (30)}
= {(1/2)/(1/2)}+ tan(60)/cos(30)
= 1 +{sqrt(3)}{2/sqrt(3)}
= 1+2 = 3................................Ans

Q. sin300/sin240 - tan150/tan 240

Sol {sin(360 -60)/sin(180+60)} - {tan(180 - 30)/tan(18+60)}
={-sin(60)/-sin(60)} - {-tan(30)/tan(60)}
= 1 + {1/sqrt(3)}/{sqrt(3)}
= 1+3 = 4.......................Ans

sin150/ cos300 - tan300/cos330

sin150= 0.5
cos300= 0.5
tan300= -1.732050808
cos330= 0.866025404
put these values to get the answer as 3


is something missing in the second one