Algebra problem help!!!!!

I have to simplify (a^2-b^2) over (-2a^2-ab+b^2). Please help. I'm confused.

(a^2-b^2) / (-2a^2-ab+b^2)

factor fully.

(a-b)(a+b) / -(2a^2 +ab -b^2)

(a-b)(a+b) / -(2a-b)(a+b)

NOTE that (a+b) / (a+b) = 1, so they essentially cancel each other out, leaving you with

(a-b) / -(2a-b)

if you want, factor the negative back in to the bracketed section for a more complete answer.

(a-b) / (-2a +b)

(a-b) / (b-2a)

can't simplify further, give restrictions.

(a^2-b^2) = (a+b)(a-b)

(-2a^2-ab+b^2) = (-2a+b)(a+b)

simplify - remove like terms in numerator & denominator (a+b)

= (a-b)/(-2a+b)

Factor the numerator. (a+b)(a-b)
Then factor the denominator. (-2a+b)(a+b)

You should be able to figure it out from here.

(a-b)(a+b)/(-2a+b)(a+b)
-(a-b)/(2a-b)