Need help on SURDS - expanding brackets

what is the answers to:


(1 - 3 square-rooted ) (2 + 3 square-rooted)


AND can you please tell me HOW you worked it out step-by-step

(1 - √3)(2 + √3)

Multiply everything in the first bracket by everything in the second bracket and add it all up:

1 x 2 = 2
1 x +√3 = √3
-√3 x 2 = -2√3
-√3 x √3 = -3

2 + √3 - 2√3 - 3 = -1 - √3

solution: (1 - 3 square-rooted ) (2 + 3 square-rooted)
(-2 square rooted)(5 square rooted)
mutiply both of them
(-10 square rooted)
we cant take square root of a negative number so take its reciprocal
(1/10(only 10 is square rooted not 1)
we cannot have radical sign(sign of square root ) in denominator so to remove it we shall take its surd
(surd means to multiply and divide any numer with the value of denominator {i know u didnot understand but after seeing the steps you will know about surd} )
so,
{10 is square rooted } (1/10 {10 is squre rooted}) (10{square rooted }/10{squre rooted})
it will become 10(squre rooted)/10(power 2 with radical sign)
then, 10(square rooted )/10 (answer)

(1 - √3) (2 + √3)
= 2 + √3 - 2√3 - √3√3
= 2 - √3 - √(3*3)
= 2 -√3 - 3
= -1 - √3

Just expand it as you expand (1-x)(2+x) and the x= rt3 so x^2 = 3. Finished!