17x^3y^2 - 34x^4y^2
You'd do (17x^3y^2) = 34x^4y^2
Then
17x^3y^2/17x^3y^2 = 1 and 34x^4y^2/17x^3y^2 = 2x
so 1 = 2x = 1/2 = x right?
You'd do (17x^3y^2) = 34x^4y^2
Then
17x^3y^2/17x^3y^2 = 1 and 34x^4y^2/17x^3y^2 = 2x
so 1 = 2x = 1/2 = x right?
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17x^3y^2 - 34x^4y^2=17x³y²(1-2x)