How to do this math problem

Solve:
3^(2y-4)=9^(3y+2)

It is confusing for me when the variables are in the exponents

first, break the 9 down. you get 3^2, right? now since the bases are equal (3 and 3), you can set the exponents equal to each other, getting 2y-4=2(3y+2). solve for y from there. :)

-2

ans

-(3^2y)/81=9^3y*81
(-3^2y)/(9^3y) =81*81
(-3^2y)/(9^3y) =6561
do like this in same process