I need help on this (trigonometry) 10 points!

If tanA = 2/3 and sinB = 5/√41 and angles A and B are in Quadrant I, find the value of tan(A + B)

Thanks in Advance!

(√41)^2 - 5^2 = 41-25 = 16, so other side of triangle is √16 = 4, so tanB = 5/4

tan(A+B) = (tanA+tanB) / (1-tanAtanB) = (2/3+5/4) / (1-(2/3)(5/4)) = 23/2