Write the equation for the parabola in the form y=a(x - h)^2+k
A) with a y-intercept 10, x-intercept 2, and equation of axis of symmetry x-3=0
I know this is easy but I can't get it for some reason. Can you guys just tell me how to do it rather than give me the answer. Or both lol
A) with a y-intercept 10, x-intercept 2, and equation of axis of symmetry x-3=0
I know this is easy but I can't get it for some reason. Can you guys just tell me how to do it rather than give me the answer. Or both lol
-
y = a(x - h)² + k
"axis of xymmetry x - 3 = 0"
h = 3
"y-intercept = 10"
10 = a(0 - 3)² + k
k = 10 - 9a
"x-intercept = 2"
0 = a(2 - 3)² + k
k = -a
10 - 9a = -a
10 = 8a
a = 1.25
k = -1.25
y = 1.25(x - 3)² - 1.25
http://www.flickr.com/photos/dwread/5666…
"axis of xymmetry x - 3 = 0"
h = 3
"y-intercept = 10"
10 = a(0 - 3)² + k
k = 10 - 9a
"x-intercept = 2"
0 = a(2 - 3)² + k
k = -a
10 - 9a = -a
10 = 8a
a = 1.25
k = -1.25
y = 1.25(x - 3)² - 1.25
http://www.flickr.com/photos/dwread/5666…