Pre-Calculus/Trig Help Please

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Given v = < 3, 5 > and u = < -2, 6 >

a) Find |v|

b) Find 2v -3u


For question "a" you simply have to plug in what you are given for "v" in the equation |v|.

|< 3| and | 5 >|

Therefore, the answer would be: All real numbers less than 3 but greater than 5.


For question "b" you will do the same thing.

2 (< 3) - 3 (5 >)

First, you should take away the less than and greater than signs in order to create a starting point for your answer. Remember, you have to plug in numbers that are less than 3 and greater than 5, not 3 or 5.

2(2)-3(6)= -14

Next, you will take the next two possible numbers for both (as long as it is any number less than 3 or greater than 5 it will work):

2(1)-3(7)= -19

See how we're not decreasing from -14? Therefore, your answer will be: All real numbers less than or equal to -14.


If I made any mistakes please correct me.

I was completely wrong with both of them. Now that I look at the problem again with the link you've provided, I copied the question incorrectly, and therefore gave incorrect answers. The answer to A was 4 and the answer to B was 2(4)-3(5)=-7 , 2(4)-3(-1)=1; answer: All Real Numbers between -7 and 11

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