Write the following complex number in trigonometric form:
5-5i
5-5i
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If z=a+bi than z=r*(cos(φ)+i*sin(φ))
where
r=√(a²+b²) and
φ=arctan(b/a)
In your exemple we have
r=√(5²+5²)=5*√2 and
φ=arctan(-5/5)=7π/4
=> z=5*√2*(cos(7π/4)+i*sin(7π/4))
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where
r=√(a²+b²) and
φ=arctan(b/a)
In your exemple we have
r=√(5²+5²)=5*√2 and
φ=arctan(-5/5)=7π/4
=> z=5*√2*(cos(7π/4)+i*sin(7π/4))
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