Write an equation for the line that passes through the points (0, -6) and (-3, 0).

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y = -2x - 6
y = -2x - 3
y = -1/2x - 6
y = -1/2x - 3

The general form of a linear equation is y = mx + b, where m is the slope and b is the y-intercept.

So, substituting the given (x,y) points, you have:

- 6 = 0*m + b = b

and

0 = -3m + b = -3m - 6, thus m = - 2

Then y = -2x - 6

Gradient= Change in y/Change in x
=6/-3
=-2

y-y1=m(x-x1)
y-0= -2(x+3)
y=-2x-6

A = 0, B = -6, C = -3, D = 0

AB + CD
AC + BD
AD + BC

36, 72, 108, 144

y=-2x-6