Could you help me untangle this,please?
The book says......
It follows from the definition of conditional probability that
P(M/C int S)=P(C int M/S) / P(C/S)
Note,however,that C and S are independent so P(C/S)=P(C).
......................................…
I thought P(M/C int S)=P(C int S int M)/P(C int S) ,any ideas how to get the author's version?
Any help appreciated,thank you.
The book says......
It follows from the definition of conditional probability that
P(M/C int S)=P(C int M/S) / P(C/S)
Note,however,that C and S are independent so P(C/S)=P(C).
......................................…
I thought P(M/C int S)=P(C int S int M)/P(C int S) ,any ideas how to get the author's version?
Any help appreciated,thank you.
-
... P [ M / ( C∩S ) ]
= P [ M ∩ ( C ∩ S ) ] / P( C ∩ S )
= P [ ( C ∩ M ) ∩ S ] / P( C ∩ S ) ......... (1)
_______________________________
Now,
P [ ( C ∩ M ) / S ] = P [ ( C ∩ M ) ∩ S ] / P( S )
so that
P [ ( C ∩ M ) ∩ S ] = P [ ( C ∩ M ) / S ] • P( S ) .............. (2)
________________________________
Also,
P ( C / S ) = P ( C ∩ S ) / P( S )
so that
P ( C ∩ S ) = P ( C / S ) • P( S ) ....................................... (3)
_________________________________
Using ( 2 ) and (3) in (1),
P [ M / ( C ∩ S ) ] = P [ ( C ∩ M ) / S ] • P( S ) / P ( C / S ) • P( S )
. . . . . . . . . . . . . . = P [ ( C ∩ M ) / S ] / P ( C / S )
__________________________________
HappyTo Help !
__________________________________
= P [ M ∩ ( C ∩ S ) ] / P( C ∩ S )
= P [ ( C ∩ M ) ∩ S ] / P( C ∩ S ) ......... (1)
_______________________________
Now,
P [ ( C ∩ M ) / S ] = P [ ( C ∩ M ) ∩ S ] / P( S )
so that
P [ ( C ∩ M ) ∩ S ] = P [ ( C ∩ M ) / S ] • P( S ) .............. (2)
________________________________
Also,
P ( C / S ) = P ( C ∩ S ) / P( S )
so that
P ( C ∩ S ) = P ( C / S ) • P( S ) ....................................... (3)
_________________________________
Using ( 2 ) and (3) in (1),
P [ M / ( C ∩ S ) ] = P [ ( C ∩ M ) / S ] • P( S ) / P ( C / S ) • P( S )
. . . . . . . . . . . . . . = P [ ( C ∩ M ) / S ] / P ( C / S )
__________________________________
HappyTo Help !
__________________________________