A canister is dropped from a helicopter hovering 500m above the ground. Unfortunately, the canister's parachute does not open. The canister has been designed to withstand an impact speed of 100 m/s. Will it burst? (use a = -9.8 m/s^2)
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v^2 - u^2 = 2as
v^2 = 2*9.8*500
v = 98.99 m/s => no it won't burst
v^2 = 2*9.8*500
v = 98.99 m/s => no it won't burst
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Thanks and best regards.
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potential energy into kinetic energy; m g h = 1/2 m v²
as the weight can be ignored we get; g h = 1/2 v²
so the final velocity is; V = √ ( 2 g h )
Its a nasty question; √ 9810 = 98.994949 m/s final velocity or rounded to 99 m/s.
But its dropped from a HELICOPTER, and those things stay UP by blowing air DOWN at a significant volume and speed .... which would, I think, help accellerate the cannister a tad, possibly enoug to make it reach 100 m/s.
as the weight can be ignored we get; g h = 1/2 v²
so the final velocity is; V = √ ( 2 g h )
Its a nasty question; √ 9810 = 98.994949 m/s final velocity or rounded to 99 m/s.
But its dropped from a HELICOPTER, and those things stay UP by blowing air DOWN at a significant volume and speed .... which would, I think, help accellerate the cannister a tad, possibly enoug to make it reach 100 m/s.