Find the mean and standard deviation of the following set of data. 4 6 8 10 12 14

(4 + 6 + 8 + 10 + 12 + 14) / 6 = 9

(4 - 9)^2 = 25
(6 - 9)^2 = 9
(8 - 9)^2 = 1
(10 - 9)^2 = 1
(12 - 9)^2 = 9
(14 - 9)^2 = 25

√[(25 + 9 + 1 + 1 + 9 + 25) / 6]
√(70/6)
√(35/3)
3.4156502553198661277403462268404
3.42

Edit.....since the set of data is the complete population you divide by n and NOT (n - 1)
if these numbers had been chosen from a greater group of numbers. you would divide by n - 1

mean = 9 (it's just the average)
std. deviation = √(14)

Use this formula for standard deviation:

std. dev = √[Σ(x - a)^2/(n - 1)]
where x is each value in the set of numbers,
a is the average of the values,
and n is the number of numbers in the set of numbers.

Cheers!

Mean = 9
SD =3.74