∫(7+tan(x))^12 sec^2(x) dx
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you need to use U substitution
say that U=7 + tan(x)
dU=sec^2(x)dx (you take the derivative of U)
so using substitution, the integral is now ∫(U)^12*du
now, integrate. the integral of U^12 is (U^13)/13
now substitute back in what U is equal to... (7+tanx)^13/13
that is your answer
say that U=7 + tan(x)
dU=sec^2(x)dx (you take the derivative of U)
so using substitution, the integral is now ∫(U)^12*du
now, integrate. the integral of U^12 is (U^13)/13
now substitute back in what U is equal to... (7+tanx)^13/13
that is your answer
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Use simple u-substitution:
∫(7 + tan(x))^(12) * sec²(x) dx
u = 7 + tan(x)
du = sec²(x) dx
∫(u^12) du
= u^13/(13) + C = (7 + tan(x))^(13)/13 + C
∫(7 + tan(x))^(12) * sec²(x) dx
u = 7 + tan(x)
du = sec²(x) dx
∫(u^12) du
= u^13/(13) + C = (7 + tan(x))^(13)/13 + C
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Try wolframalpha.com. Type in integrate followed by the problem. It will also show you the steps :)