Log base 5 (log base 2 (log base 6 X))=0......solving for x, help!

Can someone tell me how I would go about solving for x.

When we have buncha logs, we start from outside to inside.And wehn converting to exponential form: log[m]a = n ----> m^n = a

log[5](log[2](log[6]x)) = 0

Convert to exponential form:
5^0 = log[2](log[6]x)
1 = log[2](log[6]x)

Now convert to exponential form again.
2^1 = log[6]x
2 = log[6]x

Lastly do conver it again.
6^2 = x
36 = x

Thus, x = 36 :D

Hope this helps :D

log_5 (log_2 (log_6 x)) = 0
log_2 (log_6 x) = 1
log_6 x = 2
x = 6^2 = 36