Evaluate the indefinite integral of 3-cos*pix/2 dx, from 0 to 1

... ∫ { 3 - cos (πx/2) } dx ... on [ 0, 1 ]

= 3[ x ] - (2/π) [ sin (πx/2) ]

= 3[ (1) - (0) ] - (2/π)[ ( sin π/2 ) - ( sin 0 ) ]

= 3( 1 ) - (2/π)[ (1) - (0) ]

= 3 - (2/π) ........................................… Ans.
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