Please Help, how to simplify: x^4/x^-5

Recall that:

aⁿ/a^(-b) = a^(n - (-b)) = a^(n + b)

You are subtracting 4 by -5, yielding "adding both exponents". Therefore:

x^(4)/x^(-5)
= x^(4 - (-5))
= x^(4 + 5)
= x^9

I hope this helps!

If this is a fraction with x to the power of 4 on the top and x to the power of negative 5 on the bottom:

When you have a fraction, it's the same thing as a division question. Essentially you're dividing x^4 by x^-5. Whenever we divide powers, we subtract the exponents. So, basically, you have:

x^4/x^-5
= x^(4-[-5])
= x^9

So the final answer would be x^9.

Hope this helps!!!

If the exponent is negative, try to make it positive by flipping it. (ex: 2^-1 = 1/2) so you would get x^4 * x^5. The rule of exponent tells you to add the exponents when the bases are the same and when you are multiplying, so the answer would be x^9 :)

law of exponenst; divide the bases, subtract the exponents

x^4 / x^-5

x^ (4-(-5))

x^ (4+5)

x^ 9

You just subtract the 2 powers when dividing with the same variable. 4-(-5)=9. So, the answer is x^9

just make the numers ssaaler it wkre 4 me eeetso jus wok hrdyh and becom modelling

when you divide exponents, you subtract them. 4- (-5) = 9 so the answer is x^9

What's x^-5?

It's 1/x^5

so x^4/x^-5 = x^4 * x^5 = x^(4 + 5) = x^9

x^4/x^(- 5)
x^4(x^5)
x^9

x^4/x^-5=x^(4--5)=x^9