It says to find an equation for the hyperbola described:
Vertices at (-3,0) and (3,0); asymptote line of y=4x.
I'm not sure how to find the equation with just the information given, I only get as far as knowing which form the equation is in. Please help.
Vertices at (-3,0) and (3,0); asymptote line of y=4x.
I'm not sure how to find the equation with just the information given, I only get as far as knowing which form the equation is in. Please help.
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Standard hyperbola equation: x²/a²-y²/b²=1
From the vertices positions you get a=3.
The asymptote equation is y=(b/a)x so from the asymptote you get b/a=4 or b=4a=12.
So the equation is:x²/9-y²/144=1
Good luck.
From the vertices positions you get a=3.
The asymptote equation is y=(b/a)x so from the asymptote you get b/a=4 or b=4a=12.
So the equation is:x²/9-y²/144=1
Good luck.