How would I go about finding the sum of squares of roots
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How would I go about finding the sum of squares of roots

[From: ] [author: ] [Date: 11-04-25] [Hit: ]
?Roots: (approx) 2.155, -3.658, 4.......
This is the equation I need to find it for:
X^4 - 17x^3 - 24x^2 + 310

Your help is greatly appreciated :D

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x^4 - 17x^3 - 24x^2 + 310

Assuming this has got roots a b c d then

(x - a)(x - b)(x - c)(x - d)

= x^4-(a + b + c + d)x^3 + (ab + ac + ad + bc + bd + cd)x^2 + ... (other terns not required)

from above

a + b + c + d = 17 (comparing coefficients)

now ab + ac + ad + bc + bd + cd = - 24

(a + b + c + d)^2 = a^2 + b^2 + c^2 + d^2 + 2(ab + ac + ad + bc + bd + cd)
or 17^2 = a^2 + b^2 + c^2 + d^ - 2 * 24

or a^2 + b^2 + c^2 + d^2 = 17^2 + 2*24 = 289 + 48 or 337

so sum = 17
sum of squares of roots = 337

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ANSWER: SUM OF SQUARES OF ROOTS = 556.98

Why??

Roots: (approx) 2.155, -3.658, 4.122 and -14.879

AVERAGE OF ROOTS = -12.259


SUM OF SQUARES OF ROOTS = (2.155 +12.259)² + (-3.658 -12.259)² + (4.122 -12.259)² +
(-14.879 -12.259)² = 556.98

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Let x1, x2, x3, x4 be the real or complex roots of x^4 - 17x^3 - 24x^2 + 310.
Then
x^4 - 17x^3 - 24x^2 + 310 = (x - x1)(x - x2)(x - x3)(x - x4) =
................ .................. . = x^4 - (x1 + x2 + x3 + x4)x^3 + (x1x2 + x1x3 + ...)x^2 + ...
hence

x1 + x2 + x3 + x4 = 17
x1x2 + x1x3 + x1x4 + x2x3 + x2x4 + x3x4 = -24

x1^2 + x2^2 +x3^2+x4^2 = (x1+x2+x3+x4)^2 - 2(x1x2 + ... + x3x4) = 17^2 - 2(-24) = 337

bye

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