Can some one please help me out with a math problem its algebra one.. :/

Ab is a diameter of a circle. The coordinates of A are (-1,3) and the coordinates of B are (-5,9). Find the center of the circle. (If you guys can explain to me how to do this it would really help me out, please and thank you):

Since the center of a circle is coincident with the midpoint of any diameter of the circle, use the midpoint formula to find the midpoint of the line segment between the two given points:

x = (-1-5)/2 = -6/2 = -3
y = (3+9)/2 = 12/2 = 6

The midpoint of the circle is (x,y) = (-3, 6)

not algebra, it is circle theorem

diameter is a line that is AB long

Easiest way to solve is to graph this to find the centre using a compass, and bisecting the line and reading the coordinates

alternatively working it through the coordinates to find the midpoint...

Just find the Midpoint of those two coordinates

the midpoint formula is: the averages of the x's and the averages of the y's

-1+-5 then divide by 2
-6/2
x= -3

3+9 then divide by 2
12/2
y= 6
so its (-3,6)

use the midpoint formula, (x1-x2/2, y1-y2/2)

half of ab is the center, as the diameter is 2r, so it goes through the center.
So:

-3,6
I think. You could graph it out to.

You would use the midpoint formula, which finds the midpoint between two coordinates. This site will show you how.
http://www.purplemath.com/modules/midpoi…

x co-ord is given by [ (-1) + (-5) ] / 2 = - 3
y co-ord is given by [ 3 + 9 ] / 2 = 6

C ( - 3 , 6 )