Calculus help please

let f (x ,y) = (xy^2 - y) ^5

∂f / ∂x =

∂f / ∂y =

thank you

∂f / ∂x (Taking the derivative w.r.t x and treating y as a constant) = 5(xy² -y)^4 * (y²)

∂f / ∂y (Taking the deriative w.r.t y and treating x as a constant) = 5(xy² - y)^4 * (2xy - 1)

df/dx = 5y^6(xy-1)^4

df/dy = 5y^4(xy-1)^4 (2xy-1)


There's a lot to type out...
Use this: http://www.wolframalpha.com/input/?i=d%2Fdy++%28xy^2+-+y%29+^5

∂f / ∂x= 5(xy^2-y)^4(y^2) = 5y^2(xy^2-y)
∂f / ∂y =5(xy^2-y)^4(2xy-1) = (10xy-5)(xy^2-y)^4