Help in Independence Probability Again

[From: ] [author: ] [Date: 11-04-22] [Hit: ]

therefore chance is 0.03125 to not see a headsthere is a 1/6 probability of rolling a 6, therefore chance is 0.015625 to not see a heads(1/6)*(0.50) + (1/6)*(0.25) + (1/6)*(0.......

there is a 1/6 probability of rolling a 4, therefore chance is 0.0625 to not see a heads
there is a 1/6 probability of rolling a 5, therefore chance is 0.03125 to not see a heads
there is a 1/6 probability of rolling a 6, therefore chance is 0.015625 to not see a heads

(1/6)*(0.50) + (1/6)*(0.25) + (1/6)*(0.125) + (1/6)*(0.0625) + (1/6)*(0.03125) + (1/6)*(0.015625)
(1/6)*(0.50 + 0.25 + 0.125 + 0.0625 + 0.03125 + 0.015625) = 0.1640625

If you like factions better:
(1/6)(1/2 + 1/4 + 1/8 + 1/16 + 1/32 + 1/64) = (1/6)(32/64 + 16/64 + 8/64 + 4/64 + 2/64 + 1/64)
(1/6)(1/2 + 1/4 + 1/8 + 1/16 + 1/32 + 1/64) = (1/6)(63/64)
(1/6)(1/2 + 1/4 + 1/8 + 1/16 + 1/32 + 1/64) = 63/384

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The probability of rolling any number n is 1/6

Let P(n) = probability tossing no heads given n number of tosses.

P(1) = 1/2
P(2) = 1/4
P(3) = 1/8
P(4) = 1/16
P(5) = 1/32
P(6) = 1/64

Hence ( 1/2 + 1/4 + 1/8 + 1/16 + 1/32 + 1/64 ) • (1/6) = (63/64)•(1/6) = 63/384

Hope this helps you!

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