Please someone help me explain how to solve for v?
m=mo /SQUARE ROOT 1-v^2/c^2.
m=mo /SQUARE ROOT 1-v^2/c^2.
-
m/mo=1 /SQUARE ROOT 1-v^2/c^2.
mo/m=SQUARE ROOT 1-v^2/c^2.
(mo/m)^2 = 1-v^2/c^2.
(mo/m)^2 - 1 = -v^2/c^2.
1 - (mo/m)^2 = v^2/c^2.
v^2 = c^2*(1 - (mo/m)^2)
v = c*sqrt(1 - (mo/m)^2) <<<<
mo/m=SQUARE ROOT 1-v^2/c^2.
(mo/m)^2 = 1-v^2/c^2.
(mo/m)^2 - 1 = -v^2/c^2.
1 - (mo/m)^2 = v^2/c^2.
v^2 = c^2*(1 - (mo/m)^2)
v = c*sqrt(1 - (mo/m)^2) <<<<
-
Assuming that mo is one term, you can simplify as follows;
1. Multiply both sides by the right side denominator yielding:
SQR(1 - v^2/c^2) * m = mo
2. Divide both sides by m yielding: SQR(1 - v^2/c^2) = mo/m
3. Square both sides yielding: 1 - v^2/c^2 = mo^2/m^2
4. Multiply both sides by c^2 yielding: c^2 - c^2*mo^2/m^2 = v^2
5. Take SQR of both sides yielding: v = SQR(c^2 - c^2*mo^2/m^2)
Q.E.D.
1. Multiply both sides by the right side denominator yielding:
SQR(1 - v^2/c^2) * m = mo
2. Divide both sides by m yielding: SQR(1 - v^2/c^2) = mo/m
3. Square both sides yielding: 1 - v^2/c^2 = mo^2/m^2
4. Multiply both sides by c^2 yielding: c^2 - c^2*mo^2/m^2 = v^2
5. Take SQR of both sides yielding: v = SQR(c^2 - c^2*mo^2/m^2)
Q.E.D.
-
multiply both sides by the square root
m*sqrt(1-v^2/c^2)=mo
divide both sides by m
sqrt(1-v^2/c^2)=mo/m
square both sides
1-v^2/c^2=(mo/m)^2
add v^2/c^2 to both sides
1=(mo/m)^2+(v^2/c^2)
subtract (mo/m)^2 from both sides
1-(m0/m)^2=(v^2/c^2)
multiply both sides by c^2
c^2-[(mo/m)^2]*c^2=v^2
take the square root of both sides
v=sqrt{c^2-[(mo/m)^2]*c^2}
m*sqrt(1-v^2/c^2)=mo
divide both sides by m
sqrt(1-v^2/c^2)=mo/m
square both sides
1-v^2/c^2=(mo/m)^2
add v^2/c^2 to both sides
1=(mo/m)^2+(v^2/c^2)
subtract (mo/m)^2 from both sides
1-(m0/m)^2=(v^2/c^2)
multiply both sides by c^2
c^2-[(mo/m)^2]*c^2=v^2
take the square root of both sides
v=sqrt{c^2-[(mo/m)^2]*c^2}