These Math questions are absolute jibberish to me...please help!!!

1)
0.7(3x+2)=1.1-(x+3)
x=?
2)
a+(a-3)=(a+5)-(a+2)
a=?

3) A 300 m wire is cut into 3 pieces. The second piece is 3 times as long as the first. The third piece is 2 times as long as the second. How long is the first piece?

4) The employees new salary is 18,165 after getting a %5 raise. What was the salary after the increase in pay?

5) The perimeter of a college field is 92 meters and the length is 16 m more than the width. What is the length and the width?


If you're able to help me with any of these questions, that would be phenomenal!!! (also, It'd be great if you could show me how you got your answers) Thank you!!

Wow they are quite a lot of questions I must say...

1: First expand the brackets
0.7*3x+0.7*2=1.1-x-3
2.1x+1.4=1.1-3-x
Now group the x together on the left and numbers on the right and add them up
2.1x+x=1.1-3-1.4
3.1x=-3.3
x=-3.3/3.1
x=-1.0645

2: Again first expand the bracket:
a+a-3=a+5-a-2
2a=6
a=3

3: Total = 300 m
First Piece = x m
Second Piece = 3x m
Third Piece = 2(3x) = 6x m
x+3x+6x=300
10x=300
x=30 m

4: Previous Salary = x
New Salary = 18165
% increase = 5%.
Hence, x+(5/100)x=18165
x+(5x/100)=18165
Multiply all terms with 100
100x+5x=1816500
x=1816500/105
x=17300

5: Perimeter = 92m
Width = x m
Length = x+16 m
2(x+(x+16))=92
2(x+x+16)=92
2(2x+16)=92
4x+32=92
4x=92-32
4x=60
x=60/4
x=15 m

I hope that helps.. :)

Start with #3
a = 1st, b = 2nd, c =3rd
a+b+c = 300m
b=3a (3 times longer)
c = 2b
a+(3a)+2b = 300
a+(3a)+2(3a)=300
a+3a+6a = 300, a = 300/10 = 30

18,165 = (1+5%)old salary
18,167 = 1.05(s), S = 17,300

P = 2(L+W)
L=W+16
P=2(W+16+W) = 92
2(2W+16) =92
2W+16 = 46
2W = 30, W = 15 therefore L = W+16 = 31

#2
a+(a-3)=(a+5)-(a+2)
2a-3 = a+5-a-2
2a-3 = 3
2a = 6
a=3

1. 2.1+1.4=-1.9-1.1-x
3.5=-1.9-1.1-x
3.5=-3-x
.5=x

2. a+a-3=a+5-a-2
2a-3=3
2a=6
a=3

1. Perform multiplication: 2.1x+1.4=1.1-x-3 Collect like terms: 3.1x=-3.3 =>
x= -1.0645
2 Collect like terms: a+a-a+a=3+5-2 => 2a = 6 => a=3
3.let the three lengths be a, b and c
a+b+c=300 , b = 3a , c = 2b SO c = 6a Now substitute the expressions for b and c into the first equation: a+3a+6a=300 =>10a = 300 =>a = 30, b = 3a = 90, c = 2b = 180
4 18,165 = 1.05 x old salary => old salary = 18,165/1.05 = 17,300
5 P = 92 = 2L + 2W but L = W+16 Substitute into first equation 92 = 2(W+16) + 2W
Divide both sides by 2: 46 = W+16+W => 30 = 2W => W=15, L=15+16=31
Check: 2W+2L=30+62=92 Checks